Discrete Mathematics assignment

Please answer the following questions based on the conversation thus far. Requirements: answer must include explain of the reason Please complete exercise 3.9.6:

Use the following definition of absolute value to prove the given statements: If xx is a real number then the absolute value of xx|x||x| is defined by:|x|={x if x≥0−x if x<0|x|={x if x≥0−x if x<0For any real number xx |x|≥0.|x|≥0. Moreover |x|=0|x|=0 implies x=0.x=0.For any two real numbers xx and yy |x|⋅|y|=|xy|.|x|⋅|y|=|xy|.For any two real numbers xx and yy |x+y|≤|x|+|y|. For any real number xx |x|≥0.|x|≥0. Moreover |x|=0|x|=0 implies x=0.x=0. For any two real numbers xx and yy |x|⋅|y|=|xy|.|x|⋅|y|=|xy|. For any two real numbers xx and yy |x+y|≤|x|+|y|. Use a truth table to prove that 𝑝𝑝 → 𝑞𝑞 and ¬𝑞𝑞 → ¬𝑝𝑝 are logically equivalent. Here we look at multiple quantifiers.Is the statement ∀𝑥𝑥 𝑦𝑦 ∈ R ∃𝑧𝑧 ∈ R 𝑠𝑠. 𝑡𝑡. 𝑧𝑧 = 𝑥𝑥 true or false? Please prove your response. 𝑦𝑦Write the negation of the statement in part a. – it obviously must have the opposite truth value; do you find this statement easier or more difficult to prove? Is the statement ∀𝑥𝑥 𝑦𝑦 ∈ R ∃𝑧𝑧 ∈ R 𝑠𝑠. 𝑡𝑡. 𝑧𝑧 = 𝑥𝑥 true or false? Please prove your response. 𝑦𝑦 Write the negation of the statement in part a. – it obviously must have the opposite truth value; do you find this statement easier or more difficult to prove? Please complete exercise 3.9.6:

Use the following definition of absolute value to prove the given statements: If xx is a real number then the absolute value of xx|x||x| is defined by:|x|={x if x≥0−x if x<0|x|={x if x≥0−x if x<0For any real number xx |x|≥0.|x|≥0. Moreover |x|=0|x|=0 implies x=0.x=0.For any two real numbers xx and yy |x|⋅|y|=|xy|.|x|⋅|y|=|xy|.For any two real numbers xx and yy |x+y|≤|x|+|y|.Use a truth table to prove that 𝑝𝑝 → 𝑞𝑞 and ¬𝑞𝑞 → ¬𝑝𝑝 are logically equivalent.Here we look at multiple quantifiers.Is the statement ∀𝑥𝑥 𝑦𝑦 ∈ R ∃𝑧𝑧 ∈ R 𝑠𝑠. 𝑡𝑡. 𝑧𝑧 = 𝑥𝑥 true or false? Please prove your response. 𝑦𝑦Write the negation of the statement in part a. – it obviously must have the opposite truth value; do you find this statement easier or more difficult to prove? For any real number xx |x|≥0.|x|≥0. Moreover |x|=0|x|=0 implies x=0.x=0.For any two real numbers xx and yy |x|⋅|y|=|xy|.|x|⋅|y|=|xy|.For any two real numbers xx and yy |x+y|≤|x|+|y|. Is the statement ∀𝑥𝑥 𝑦𝑦 ∈ R ∃𝑧𝑧 ∈ R 𝑠𝑠. 𝑡𝑡. 𝑧𝑧 = 𝑥𝑥 true or false? Please prove your response. 𝑦𝑦Write the negation of the statement in part a. – it obviously must have the opposite truth value; do you find this statement easier or more difficult to prove?

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